类 DebugTreeNodeStream
- java.lang.Object
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- org.antlr.runtime.debug.DebugTreeNodeStream
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- 所有已实现的接口:
IntStream,TreeNodeStream
public class DebugTreeNodeStream extends java.lang.Object implements TreeNodeStream
Debug any tree node stream. The constructor accepts the stream and a debug listener. As node stream calls come in, debug events are triggered.
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字段概要
字段 修饰符和类型 字段 说明 protected TreeAdaptoradaptorprotected DebugEventListenerdbgprotected booleaninitialStreamStateprotected TreeNodeStreaminputprotected intlastMarkerTrack the last mark() call result value for use in rewind().
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构造器概要
构造器 构造器 说明 DebugTreeNodeStream(TreeNodeStream input, DebugEventListener dbg)
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方法概要
所有方法 实例方法 具体方法 修饰符和类型 方法 说明 voidconsume()java.lang.Objectget(int i)Get a tree node at an absolute indexi; 0..n-1.java.lang.StringgetSourceName()Where are you getting symbols from? Normally, implementations will pass the buck all the way to the lexer who can ask its input stream for the file name or whatever.TokenStreamgetTokenStream()If the tree associated with this stream was created from aTokenStream, you can specify it here.TreeAdaptorgetTreeAdaptor()What adaptor can tell me how to interpret/navigate nodes and trees.java.lang.ObjectgetTreeSource()Where is this stream pulling nodes from? This is not the name, but the object that provides node objects.intindex()Return the current input symbol index 0..n where n indicates the last symbol has been read.intLA(int i)Get int at current input pointer + i ahead where i=1 is next int.java.lang.ObjectLT(int i)Get tree node at current input pointer +kahead wherek==1is next node.intmark()Tell the stream to start buffering if it hasn't already.voidrelease(int marker)You may want to commit to a backtrack but don't want to force the stream to keep bookkeeping objects around for a marker that is no longer necessary.voidreplaceChildren(java.lang.Object parent, int startChildIndex, int stopChildIndex, java.lang.Object t)Replace children ofparentfrom indexstartChildIndextostopChildIndexwitht, which might be a list.voidreset()Reset the tree node stream in such a way that it acts like a freshly constructed stream.voidrewind()Rewind to the input position of the last marker.voidrewind(int marker)Reset the stream so that next call to index would return marker.voidseek(int index)Set the input cursor to the position indicated by index.voidsetDebugListener(DebugEventListener dbg)voidsetUniqueNavigationNodes(boolean uniqueNavigationNodes)It is normally this object that instructs the node stream to create unique nav nodes, but to satisfy interface, we have to define it.intsize()Only makes sense for streams that buffer everything up probably, but might be useful to display the entire stream or for testing.java.lang.StringtoString(java.lang.Object start, java.lang.Object stop)Return the text of all nodes fromstarttostop, inclusive.
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字段详细资料
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dbg
protected DebugEventListener dbg
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adaptor
protected TreeAdaptor adaptor
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input
protected TreeNodeStream input
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initialStreamState
protected boolean initialStreamState
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lastMarker
protected int lastMarker
Track the last mark() call result value for use in rewind().
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构造器详细资料
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DebugTreeNodeStream
public DebugTreeNodeStream(TreeNodeStream input, DebugEventListener dbg)
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方法详细资料
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setDebugListener
public void setDebugListener(DebugEventListener dbg)
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getTreeAdaptor
public TreeAdaptor getTreeAdaptor()
从接口复制的说明:TreeNodeStreamWhat adaptor can tell me how to interpret/navigate nodes and trees. E.g., get text of a node.- 指定者:
getTreeAdaptor在接口中TreeNodeStream
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get
public java.lang.Object get(int i)
从接口复制的说明:TreeNodeStreamGet a tree node at an absolute indexi; 0..n-1. If you don't want to buffer up nodes, then this method makes no sense for you.- 指定者:
get在接口中TreeNodeStream
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LT
public java.lang.Object LT(int i)
从接口复制的说明:TreeNodeStreamGet tree node at current input pointer +kahead wherek==1is next node.k<0indicates nodes in the past. SoLT(-1)is previous node, but implementations are not required to provide results fork < -1.LT(0)is undefined. Fork<=n, returnnull. ReturnnullforLT(0)and any index that results in an absolute address that is negative.This is analogous to
TokenStream.LT(int), but this returns a tree node instead of aToken. Makes code generation identical for both parser and tree grammars.- 指定者:
LT在接口中TreeNodeStream
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LA
public int LA(int i)
从接口复制的说明:IntStreamGet int at current input pointer + i ahead where i=1 is next int. Negative indexes are allowed. LA(-1) is previous token (token just matched). LA(-i) where i is before first token should yield -1, invalid char / EOF.
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mark
public int mark()
从接口复制的说明:IntStreamTell the stream to start buffering if it hasn't already. Return current input position, index(), or some other marker so that when passed to rewind() you get back to the same spot. rewind(mark()) should not affect the input cursor. The Lexer track line/col info as well as input index so its markers are not pure input indexes. Same for tree node streams.
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index
public int index()
从接口复制的说明:IntStreamReturn the current input symbol index 0..n where n indicates the last symbol has been read. The index is the symbol about to be read not the most recently read symbol.
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rewind
public void rewind(int marker)
从接口复制的说明:IntStreamReset the stream so that next call to index would return marker. The marker will usually be index() but it doesn't have to be. It's just a marker to indicate what state the stream was in. This is essentially calling release() and seek(). If there are markers created after this marker argument, this routine must unroll them like a stack. Assume the state the stream was in when this marker was created.
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rewind
public void rewind()
从接口复制的说明:IntStreamRewind to the input position of the last marker. Used currently only after a cyclic DFA and just before starting a sem/syn predicate to get the input position back to the start of the decision. Do not "pop" the marker off the state. mark(i) and rewind(i) should balance still. It is like invoking rewind(last marker) but it should not "pop" the marker off. It's like seek(last marker's input position).
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release
public void release(int marker)
从接口复制的说明:IntStreamYou may want to commit to a backtrack but don't want to force the stream to keep bookkeeping objects around for a marker that is no longer necessary. This will have the same behavior as rewind() except it releases resources without the backward seek. This must throw away resources for all markers back to the marker argument. So if you're nested 5 levels of mark(), and then release(2) you have to release resources for depths 2..5.
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seek
public void seek(int index)
从接口复制的说明:IntStreamSet the input cursor to the position indicated by index. This is normally used to seek ahead in the input stream. No buffering is required to do this unless you know your stream will use seek to move backwards such as when backtracking. This is different from rewind in its multi-directional requirement and in that its argument is strictly an input cursor (index). For char streams, seeking forward must update the stream state such as line number. For seeking backwards, you will be presumably backtracking using the mark/rewind mechanism that restores state and so this method does not need to update state when seeking backwards. Currently, this method is only used for efficient backtracking using memoization, but in the future it may be used for incremental parsing. The index is 0..n-1. A seek to position i means that LA(1) will return the ith symbol. So, seeking to 0 means LA(1) will return the first element in the stream.
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size
public int size()
从接口复制的说明:IntStreamOnly makes sense for streams that buffer everything up probably, but might be useful to display the entire stream or for testing. This value includes a single EOF.
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reset
public void reset()
从接口复制的说明:TreeNodeStreamReset the tree node stream in such a way that it acts like a freshly constructed stream.- 指定者:
reset在接口中TreeNodeStream
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getTreeSource
public java.lang.Object getTreeSource()
从接口复制的说明:TreeNodeStreamWhere is this stream pulling nodes from? This is not the name, but the object that provides node objects.- 指定者:
getTreeSource在接口中TreeNodeStream
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getSourceName
public java.lang.String getSourceName()
从接口复制的说明:IntStreamWhere are you getting symbols from? Normally, implementations will pass the buck all the way to the lexer who can ask its input stream for the file name or whatever.- 指定者:
getSourceName在接口中IntStream
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getTokenStream
public TokenStream getTokenStream()
从接口复制的说明:TreeNodeStreamIf the tree associated with this stream was created from aTokenStream, you can specify it here. Used to do rule$textattribute in tree parser. Optional unless you use tree parser rule$textattribute oroutput=templateandrewrite=trueoptions.- 指定者:
getTokenStream在接口中TreeNodeStream
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setUniqueNavigationNodes
public void setUniqueNavigationNodes(boolean uniqueNavigationNodes)
It is normally this object that instructs the node stream to create unique nav nodes, but to satisfy interface, we have to define it. It might be better to ignore the parameter but there might be a use for it later, so I'll leave.- 指定者:
setUniqueNavigationNodes在接口中TreeNodeStream
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replaceChildren
public void replaceChildren(java.lang.Object parent, int startChildIndex, int stopChildIndex, java.lang.Object t)从接口复制的说明:TreeNodeStreamReplace children ofparentfrom indexstartChildIndextostopChildIndexwitht, which might be a list. Number of children may be different after this call. The stream is notified because it is walking the tree and might need to know you are monkeying with the underlying tree. Also, it might be able to modify the node stream to avoid restreaming for future phases.If
parentisnull, don't do anything; must be at root of overall tree. Can't replace whatever points to the parent externally. Do nothing.- 指定者:
replaceChildren在接口中TreeNodeStream
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toString
public java.lang.String toString(java.lang.Object start, java.lang.Object stop)从接口复制的说明:TreeNodeStreamReturn the text of all nodes fromstarttostop, inclusive. If the stream does not buffer all the nodes then it can still walk recursively from start until stop. You can always returnnullor""too, but users should not access$ruleLabel.textin an action of course in that case.- 指定者:
toString在接口中TreeNodeStream
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